(F)T=-16t^2+45t+6

Solution for (F)T=-16t^2+45t+6 equation:

()=-16F^2+45F+6

We move all terms to the left:

()-(-16F^2+45F+6)=0

We add all the numbers together, and all the variables

-(-16F^2+45F+6)=0

We get rid of parentheses

16F^2-45F-6=0

a = 16; b = -45; c = -6;
Δ = b2-4ac
Δ = -452-4·16·(-6)
Δ = 2409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2409}}{2*16}=\frac{45-\sqrt{2409}}{32}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2409}}{2*16}=\frac{45+\sqrt{2409}}{32}
$